A Player Hits A 0.05kg Golf Ball,If A 3.25kg M/S Impulse Is Imparted On The Ball,What Is Its Final Speed?

A player hits a 0.05kg golf ball,if a 3.25kg m/s impulse is imparted on the ball,what is its final speed?

 

Good Day:

Problem:

A player hits a 0.05kg golf ball,if a 3.25kg m/s impulse is imparted on the ball,what is its final speed?

Given:

m (mass) = 0.05 Kg

Vi (initial velocity) = 0 m/s

Vf (final velocity) = ? unknown

Δp (change in momentum or impulse)  = 3.25 kg.m/s

Solution:

This problem can be solve using the formula of change in momentum. Change in momentum is the same as impulse. Δp = m × (Vf - Vi) and to solve for Vf, we can use Vf = Δp/m - Vi

Vf = Δp/m - Vi

   = 3.25 kg.m/s / 0.05 Kg  - 0 m/s

   = 65 m/s - 0 m/s

   = 65 m/s

Answer:

The final velocity is 65 m/s